Computer Architecture
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NTA NET ASPIRANT ACADEMY is a training academy for College Lectures, Assistant Professor, Research Scholar and PG Students to make qualified for Assistant Professor & JRF in UGC NET / TNSET
NTA NET ASPIRANT ACADEMY is a training academy for College Lectures, Assistant Professor, Research Scholar and PG Students to make qualified for Assistant Professor & JRF in UGC NET / TNSET
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Question 1 |
Concern a disk with a sector size of 512 bytes, 2000 tracks per surface, 50 sectors per track, five double - sided platters, and average seek time of 10 milliseconds. NTA NET JUNE 2020
Given below are two statements:
Statement I: The disk has a total number of 2000 cylinders.
Statement II: 51200 bytes is not a valid block size for the disk.
In the light of the above statements, choose the correct answer from the options given below:
A | Both Statement I and Statement II are true |
B | Both Statement I and Statement II are false |
C | Statement I is true but Statement II is false |
D | Statement I is false but Statement II is true |
Question 2 |
Concern a disk with a sector size of 512 bytes, 2000 tracks per surface, 50 sectors per track, five double - sided platters, and average seek time of 10 milliseconds. NTA NET JUNE 2020
If T is the capacity of a track in bytes, and S is the capacity of each surface in bytes, then (T,S)= ______
A | (50K, 50000K) |
B | (25K, 25000K) |
C | (25K, 50000K) |
D | (40K, 36000K) |
Question 3 |
Concern a disk with a sector size of 512 bytes, 2000 tracks per surface, 50 sectors per track, five double - sided platters, and average seek time of 10 milliseconds. NTA NET JUNE 2020
What is the capacity of the disk in bytes?
What is the capacity of the disk in bytes?
A | 25,000 K |
B | 500,000 K |
C | 250,000 K |
D | 50,000 K |
Question 4 |
Concern a disk with a sector size of 512 bytes, 2000 tracks per surface, 50 sectors per track, five double - sided platters, and average seek time of 10 milliseconds. NTA NET JUNE 2020
If the disk platters rotate at 5400 rpm (Revolutions per minute), then approximately what is the maximum rotational delay?
If the disk platters rotate at 5400 rpm (Revolutions per minute), then approximately what is the maximum rotational delay?
A | 0.011 Seconds |
B | 0.11 Seconds |
C | 0.0011 Seconds |
D | 1.1 Seconds |
Question 5 |
Concern a disk with a sector size of 512 bytes, 2000 tracks per surface, 50 sectors per track, five double - sided platters, and average seek time of 10 milliseconds. NTA NET JUNE 2020
If one track of data can be transferred per revolution, then what is the data transfer rate?
If one track of data can be transferred per revolution, then what is the data transfer rate?
A | 2,850 KBytes / second |
B | 4,500 KBytes / second |
C | 5,700 KBytes / second |
D | 2,250 KBytes / second |
Question 6 |
The Reduced Instruction Set Computer (RISC) characteristics are: NTA NET DECEMBER 2019
a. Single cycle instruction execution.
b. Variable length instruction formats.
c. Instructions that manipulates operands in memory.
d. Efficient instruction pipeline.
Choose the correct characteristics from the options given below:
A | (a) and (b) |
B | (b) and (c) |
C | (a) and (d) |
D | (c) and (d) |
Question 7 |
A computer uses a memory unit of 512 K words of 32 bits each. A binary instruction code is stored in one word of the memory. The instruction has four parts: an addressing mode field to specify one of the two - addressing mode(direct and indirect), an operation code, a register code part to specify one of the 256 registers and an address part. How many bits are there in addressing mode part, an opcode part, register code part and the address part? NTA NET DECEMBER 2019
A | 1, 3, 9, 19 |
B | 1, 4, 9, 18 |
C | 1, 4, 8, 19 |
D | 1, 3, 8, 20 |
Question 8 |
A micro instruction format has microoperation field which is divided into 2 subfields F1 and F2, each of having 15 distinct microoperations, condition field CD for four status bits, branch field BR having four options used in conjunction with address field AD. The address space is of 128 memory words. The size of the micro instruction is: NTA NET December 2019
A | 19 |
B | 18 |
C | 17 |
D | 20 |
Question 9 |
An instruction is stored at location 500 with its address field at location 501. The address field has the value 400. A processor register R1 contains the number 200. Match the addressing mode (List I) given below with effective address (List II) for the given instruction: NTA NET DECEMBER 2019
List - I | List - II (Effective Address) |
---|---|
A. Direct | (i) 200 |
B. Register Indirect | (ii) 902 |
C. Index with R1 as the index register | (iii) 400 |
D. Relative | (iv) 600 |
A | A - iii; B - i; C - iv; D - ii |
B | A - i; B - ii; C - iii; D - iv |
C | A - iv; B - ii; C - iii; D - i |
D | A - iv; B - iii; C - ii; D - i |
Question 10 |
Match List - I with List - II: NTA NET DECEMBER 2019
Choose the correct options from those given below:
List - I | List - II |
---|---|
A. Micro operation | (i) Specify micro operations |
B. Micro programmed control Unit | (ii) Improve CPU Utilization |
C. Interrupts | (iii) Control memory |
D. Micro instruction | (iv) Elementary operation performed on data stored in registers |
A | A - iv; B - iii; C - ii; D - i |
B | A - iv; B - iii; C - i; D - ii |
C | A - iii; B - iv; C - ii; D - i |
D | A - iii; B - iv; C - i; D - ii |
Question 11 |
Which of the following methods are used to pass any number of parameters to the operating system through system calls? NTA NET December 2019
A | Registers |
B | Block or table in main memory |
C | Stack |
D | Block in main memory and stack |
Question 12 |
The Boolean expression AB+AB̅ + A̅C is unaffected by the value of the Boolean variable _______ ̅ NTA NET December 2019
A | A |
B | B |
C | C |
D | A, B and C |
Question 13 |
The following program is stored in the memory unit of the basic computer. Give the content of accumulator register in hexadecimal after the execution of the program. NTA NET December 2019
Location | Instruction |
---|---|
010 | CLA |
011 | ADD 016 |
012 | BUN 014 |
013 | HLT |
014 | AND 017 |
015 | BUN 013 |
016 | C1A5 |
017 | 93C6 |
A | A1B4 |
B | 81B4 |
C | A184 |
D | 8184 |
Question 14 |
Given following equation: NTA NET December 2019
(142)b + (112)b-2 = (75)8, find base b.
A | 3 |
B | 6 |
C | 7 |
D | 5 |
Question 15 |
A non - pipelined system takes 30ns to process a task. The same task can be processed in a four segment pipeline with a clock cycle of 10ns. Determine the speed up of the pipeline for 100 tasks. NTA NET December 2019
A | 3 |
B | 4 |
C | 3.91 |
D | 2.91 |
Question 16 |
Match List I and List II: NTA NET December 2019
Choose the correct option from those given below:
List - I | List - II |
---|---|
A. Isolated I/O | (i) same set of control signal for I/O and memory communication |
B. Memory mapped I/O | (ii) Separate instructions for I/O and memory communication |
C. I/O interface | (iii) requires controls signals to be transmitted between the communicating units. |
D. Asynchronous data transfer | (iv) resolve the differences in central computer and peripherals |
A | A - ii, B - iii, C - iv, D -i |
B | A - i, B - ii, C - iii, D -iv |
C | A - ii, B - i, C - iv, D -iii |
D | A - i, B - ii, C - iv, D -iii |
Question 17 |
Which of the following binary codes for decimal digits are self complementing? NTA NET December 2019
A. 8421 code
B. 2421 code
C. excess - 3 code
D. excess - 3 gray code
Choose the correct option:
A | (A) and (B) |
B | (B) and (C) |
C | (C) and (D) |
D | (A) and (D) |
Question 18 |
CMOS is a Computer Chip on the motherboard, which is: CBSE NET JULY 2018
A | RAM |
B | ROM |
C | EPROM |
D | Auxiliary storage |
Question 19 |
In RS flip - flop, the output of the flip - flop at time (t+1) is same as the output at time t, after the occurrence of a clock pulse if: CBSE NET JULY 2018
A | S = R = 1 |
B | S = 0, R = 1 |
C | S = 1, R = 0 |
D | S = R = 0 |
Question 20 |
Match the terms in List - I with the options given in List - II: CBSE NET JULY 2018
List - I | List - II |
---|---|
A. Decoder | (i) 1 line to 2n lines |
B. Multiplexer | (ii) n lines to 2n lines |
C. De multiplexer | (iii) 2n lines to 1 line |
(iv) 2n lines to 2n-1 lines |
A | A - ii, B - i, C - iii |
B | A - ii, B - iii, C - i |
C | A - ii, B - i, C - iv |
D | A - iv, B - ii, C - i |
Question 21 |
The hexadecimal equivalent of the binary integer number 110101101 is: CBSE NET JULY 2018
A | D24 |
B | 1BD |
C | 1AE |
D | 1AD |
Question 22 |
Perform the following operation for the binary equivalent of the decimal numbers (-14)10 + (-15)10 CBSE NET JULY 2018
The solution in 8 - bit representation is:
A | 11100011 |
B | 00011101 |
C | 10011101 |
D | 11110011 |
Question 23 |
Match the items in List - I and List - II CBSE NET JULY 2018
List - I | List - II |
---|---|
A. Interrupts which can be delayed when a much highest priority interrupt has occurred | (i) Normal |
B. Unplanned interrupts which occur while executing a program | (ii) Synchronous |
C. Source of interrupts is in phase with the system clock | (iii) Maskable |
(iv) Exception |
A | A - ii, B - i, C - iv |
B | A - ii, B - iv, C - iii |
C | A - iii, B - i, C - ii |
D | A - iii, B -iv, C - ii |
Question 24 |
Which of the following mapping is not used for mapping process in cache memory? CBSE NET JULY 2018
A | Associative mapping |
B | Direct mapping |
C | Set - Associative mapping |
D | Segmented - page mapping |
Question 25 |
Simplify the following using K - map: CBSE NET JULY 2018
F(A, B, C, D) = ∑ (0,1,2,8,9,12,13)
d(A, B, C, D) = ∑ (10,11,14,15)
d stands for don't care condition.
A | A + B̅ D̅ + BC |
B | A + B̅ D̅ + B̅ C̅ |
C | A̅ + B̅ C̅ |
D | A̅ + B̅ C̅ + B̅ D̅ |
Question 26 |
In 8085 microprocessor, What is the output of following program? CBSE NET JULY 2018
LDA 8000H
MVI B, 30H
ADD B
STA 8001H
LDA 8000H
MVI B, 30H
ADD B
STA 8001H
A | Read a number from input port and store it in memory |
B | Read a number from input device with address 8000H and store it in memory at location 8001H |
C | Read a number from memory at location 8000H and store it in memory location 8001H |
D | Load A with data from input device with address 8000H and display it on the output device with address 8001H |
Question 27 |
In computers subtraction is generally carried out by NTA NET December 2018
A | 9's complement |
B | 1's complement |
C | 10's complement |
D | 2's complement |
Question 28 |
Consider the following Boolean equations: NTA NET December 2018
(i) wx + w(x+y) + x(x+y)=x+wy
(ii) (wx̅(y+xz̅) + w̅x̅)y=x̅y
What can you say about the above equations?
(i) wx + w(x+y) + x(x+y)=x+wy
(ii) (wx̅(y+xz̅) + w̅x̅)y=x̅y
What can you say about the above equations?
A | (i) is true and (ii) is false |
B | (i) is false and (ii) is true Hint: |
C | Both (i) and (ii) are true |
D | Both (i) and (ii) are false |
Question 29 |
Consider the following statements: NTA NET December 2018
(i) Auto increment addressing mode is useful in creating self - relocating code.
(ii) If auto increment addressing mode is included in an instruction set architecture, then an additional ALU is required for effective address calculations.
(iii) In auto increment mode, the amount of increment depends on the size of the data item accessed.
Which of the above statements is / are true?
(i) Auto increment addressing mode is useful in creating self - relocating code.
(ii) If auto increment addressing mode is included in an instruction set architecture, then an additional ALU is required for effective address calculations.
(iii) In auto increment mode, the amount of increment depends on the size of the data item accessed.
Which of the above statements is / are true?
A | (i) and (ii) only |
B | (ii) and (iii) only |
C | (iii) only |
D | (ii) only |
Question 30 |
A computer uses a memory unit with 256K words of 32 bits each. A binary instruction code is stored in one word of memory. The instruction has four parts: an indirect bit, an operation code and a register code part to specify one of 64 registers and an address part. How many bits are there in the operation code, the register code part and the address part? NTA NET December 2018
A | 7, 6, 18 |
B | 6, 7, 18 |
C | 7, 7, 18 |
D | 18, 7, 7 |
Question 31 |
Consider the following x86 - assembly language instructions: NTA NET December 2018
MOV AL, 153
NEG AL
The contents of the destination register AL(in 8-bit binary notation), the status of Carry Flag (CF) and Sign Flag(SF) after the execution of above instructions, are
MOV AL, 153
NEG AL
The contents of the destination register AL(in 8-bit binary notation), the status of Carry Flag (CF) and Sign Flag(SF) after the execution of above instructions, are
A | AL 0110 0110; CF=0; SF=0 |
B | AL 0110 0111; CF=0; SF=1 |
C | AL 0110 0110; CF=1; SF=1 |
D | AL 0110 0111; CF=1; SF=0 |
Question 32 |
Consider a disk pack with 32 surfaces, 64 tracks and 512 sectors per pack. 256 bytes of data are stored in a bit serial manner in a sector. The number of bits required to specify a particular sector in the disk is NTA NET December 2018
A | 18 |
B | 19 |
C | 20 |
D | 22 |
Question 33 |
Consider a system with 2 level cache. Access time of Level 1 cache, Level 2 cache and main memory are 0.5ns, 5 ns and 100ns respectively. The hit rates of Level 1 and Level 2 caches are 0.7 and 0.8, respectively. What is the average access time of the system ignoring the search time within the cache? NTA NET December 2018
A | 35.20 ns |
B | 7.55 ns |
C | 20.75 ns |
D | 24.35 ns |
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